The Journal of the Indian Mathematical Society

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Squaring the Circle


     

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Let PQR be a circle with centre 0, of Which a diameter is PR. Bisect P0 at H and let T be the point of trisection of OR nearer R. Draw TQ perpendicular to PR and place the chord RS = TQ.
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  • Squaring the Circle

Abstract Views: 148  |  PDF Views: 0

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Abstract


Let PQR be a circle with centre 0, of Which a diameter is PR. Bisect P0 at H and let T be the point of trisection of OR nearer R. Draw TQ perpendicular to PR and place the chord RS = TQ.